1620-0.45x^2=0

Solution for 1620-0.45x^2=0 equation:

1620-0.45x^2=0

a = -0.45; b = 0; c = +1620;
Δ = b2-4ac
Δ = 02-4·(-0.45)·1620
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54}{2*-0.45}=\frac{-54}{-0.9}
=+60
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54}{2*-0.45}=\frac{54}{-0.9}
=-60
$